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2.51 kB
| // Light Show | |
| // Solution by Jacob Plachta | |
| using namespace std; | |
| template<typename T> T Abs(T x) { return(x<0 ? -x : x); } | |
| template<typename T> T Sqr(T x) { return(x*x); } | |
| string plural(string s) { return(Sz(s) && s[Sz(s)-1]=='x' ? s+"en" : s+"s"); } | |
| const int INF = (int)1e9; | |
| const LD EPS = 1e-12; | |
| const LD PI = acos(-1.0); | |
| bool Read(int &x) | |
| { | |
| char c,r=0,n=0; | |
| x=0; | |
| for(;;) | |
| { | |
| c=GETCHAR(); | |
| if ((c<0) && (!r)) | |
| return(0); | |
| if ((c=='-') && (!r)) | |
| n=1; | |
| else | |
| if ((c>='0') && (c<='9')) | |
| x=x*10+c-'0',r=1; | |
| else | |
| if (r) | |
| break; | |
| } | |
| if (n) | |
| x=-x; | |
| return(1); | |
| } | |
| int main() | |
| { | |
| if (DEBUG) | |
| freopen("in.txt","r",stdin); | |
| // vars | |
| int T,t; | |
| int H,N; | |
| int i,j,c,d; | |
| PR P[LIM]; | |
| static int dyn[LIM][LIM][2]; | |
| // testcase loop | |
| Read(T); | |
| Fox1(t,T) | |
| { | |
| // input | |
| Read(H),Read(N); | |
| Fox(i,N) | |
| Read(P[i].x),Read(P[i].y),P[i].y--; | |
| // sort by position | |
| sort(P,P+N); | |
| // DP | |
| Fill(dyn,-1); | |
| dyn[0][0][0]=0; | |
| Fox(i,N) | |
| Fox(j,i+1) | |
| Fox(c,2) | |
| if ((d=dyn[i][j][c])>=0) | |
| if (P[i].y==c) | |
| Max(dyn[i+1][j+1][c],d+j); // add on | |
| else | |
| { | |
| Max(dyn[i+1][j][c],d); // skip | |
| Max(dyn[i+1][1][1-c],d); // switch colour | |
| } | |
| // find answer | |
| int ans=0; | |
| Fox(j,N+1) | |
| Fox(c,2) | |
| Max(ans,dyn[N][j][c]); | |
| // output | |
| printf("Case #%d: %d\n",t,ans); | |
| } | |
| return(0); | |
| } |