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| // Cake-Cutting Committee | |
| // Solution by Jacob Plachta | |
| using namespace std; | |
| template<typename T> T Abs(T x) { return(x < 0 ? -x : x); } | |
| template<typename T> T Sqr(T x) { return(x * x); } | |
| string plural(string s) { return(Sz(s) && s[Sz(s) - 1] == 'x' ? s + "en" : s + "s"); } | |
| const int INF = (int)1e9; | |
| const LD EPS = 1e-12; | |
| const LD PI = acos(-1.0); | |
| bool Read(int& x) { | |
| char c, r = 0, n = 0; | |
| x = 0; | |
| for (;;) { | |
| c = GETCHAR(); | |
| if ((c < 0) && (!r)) | |
| return(0); | |
| if ((c == '-') && (!r)) | |
| n = 1; | |
| else if ((c >= '0') && (c <= '9')) | |
| x = x * 10 + c - '0', r = 1; | |
| else if (r) | |
| break; | |
| } | |
| if (n) | |
| x = -x; | |
| return(1); | |
| } | |
| TVAL ZERO_VAL = 0; | |
| TLAZY ZERO_LAZY = 0; | |
| struct SegTree | |
| { | |
| void UpdateValForUpdateOrLazy(TVAL& a, TLAZY v) | |
| { | |
| a += v; | |
| } | |
| void UpdateLazyForUpdateOrLazy(TLAZY& a, TLAZY v) | |
| { | |
| a += v; | |
| } | |
| TVAL CombVals(TVAL v1, TVAL v2) | |
| { | |
| return(max(v1, v2)); | |
| } | |
| int N, sz; | |
| TVAL tree[TLIM]; | |
| TLAZY lazy[TLIM]; | |
| SegTree() {} | |
| SegTree(int _N) | |
| { | |
| Init(_N); | |
| } | |
| void Init(int _N) | |
| { | |
| N = _N; | |
| for (sz = 1; sz < N; sz <<= 1); | |
| Clear(); | |
| } | |
| void Clear() | |
| { | |
| int i; | |
| Fox(i, sz << 1) | |
| tree[i] = ZERO_VAL; | |
| Fox(i, sz << 1) | |
| lazy[i] = ZERO_LAZY; | |
| } | |
| void Prop(int i) | |
| { | |
| TLAZY v = lazy[i]; | |
| lazy[i] = ZERO_LAZY; | |
| UpdateValForUpdateOrLazy(tree[i], v); | |
| if (i < sz) | |
| { | |
| int c1 = i << 1, c2 = c1 + 1; | |
| UpdateLazyForUpdateOrLazy(lazy[c1], v); | |
| UpdateLazyForUpdateOrLazy(lazy[c2], v); | |
| } | |
| } | |
| void Comp(int i) | |
| { | |
| int c1 = i << 1, c2 = c1 + 1; | |
| tree[i] = CombVals(tree[c1], tree[c2]); | |
| } | |
| TVAL Query( | |
| int a, int b, | |
| int i = 1, int r1 = 0, int r2 = -1 | |
| ) { | |
| if (r2 < 0) | |
| { | |
| Max(a, 0); | |
| Min(b, sz - 1); | |
| if (a > b) | |
| return ZERO_VAL; | |
| r2 = sz - 1; | |
| } | |
| Prop(i); | |
| if (a <= r1 && r2 <= b) | |
| return(tree[i]); | |
| int m = (r1 + r2) >> 1, c = i << 1; | |
| TVAL ret = ZERO_VAL; | |
| if (a <= m) | |
| ret = CombVals(ret, Query(a, b, c, r1, m)); | |
| if (b > m) | |
| ret = CombVals(ret, Query(a, b, c + 1, m + 1, r2)); | |
| return(ret); | |
| } | |
| void Update( | |
| int a, int b, | |
| TLAZY v, | |
| int i = 1, int r1 = 0, int r2 = -1 | |
| ) { | |
| if (r2 < 0) | |
| { | |
| Max(a, 0); | |
| Min(b, sz - 1); | |
| if (a > b) | |
| return; | |
| r2 = sz - 1; | |
| } | |
| Prop(i); | |
| if (a <= r1 && r2 <= b) | |
| { | |
| UpdateLazyForUpdateOrLazy(lazy[i], v); | |
| Prop(i); | |
| return; | |
| } | |
| int m = (r1 + r2) >> 1, c = i << 1; | |
| if (a <= m) | |
| Update(a, b, v, c, r1, m); | |
| if (b > m) | |
| Update(a, b, v, c + 1, m + 1, r2); | |
| Prop(c), Prop(c + 1), Comp(i); | |
| } | |
| }; | |
| struct Event | |
| { | |
| int x, y1, y2, c; | |
| bool s; | |
| }; | |
| const bool operator<(const Event& a, const Event& b) | |
| { | |
| return(mp(a.x, !a.s) < mp(b.x, !b.s)); | |
| } | |
| int S, N; | |
| int C[LIM], P[LIM][4]; | |
| bool IsBetween(int a, int b, int p, bool ex) | |
| { | |
| if (b < a) | |
| b += INF; | |
| if (p < a) | |
| p += INF; | |
| return ex ? a < p && p < b : a <= p && p <= b; | |
| } | |
| int GetPosAfter(int a, int p) | |
| { | |
| if (p < a) | |
| p += INF; | |
| return(p - a); | |
| } | |
| int SolveForLine(vector<int> h) | |
| { | |
| int i, j, s; | |
| // compare all pieces against dividing line, and assemble line sweep events | |
| int base = 0; | |
| vector<int> CY; | |
| vector<Event> E; | |
| Fox(i, N) | |
| { | |
| // full intersection? | |
| if ( | |
| (IsBetween(P[i][0], P[i][2], h[0], 0) || IsBetween(P[i][3], P[i][1], h[0], 0)) && | |
| (IsBetween(P[i][0], P[i][2], h[1], 0) || IsBetween(P[i][3], P[i][1], h[1], 0)) | |
| ) | |
| { | |
| base += C[i]; | |
| continue; | |
| } | |
| // look for orientation of line segments such that at least one spans crosses from the 1st to the 2nd half | |
| Fox(s, 2) | |
| { | |
| int p[4]; | |
| memcpy(p, P[i], sizeof(p)); | |
| if (s) | |
| reverse(p, p + 4); | |
| // check which points are on their required halves | |
| bool bx[2], by[2]; | |
| Fox(j, 2) | |
| { | |
| bx[j] = IsBetween(h[0], h[1], p[j * 2], 0); | |
| by[j] = IsBetween(h[1], h[0], p[j * 2 + 1], 0); | |
| } | |
| // neither line segment is entirely valid? | |
| if ((!bx[0] || !by[0]) && (!bx[1] || !by[1])) | |
| continue; | |
| assert(bx[0] + by[0] + bx[1] + by[1] >= 3); // other one must be at least half-valid | |
| // map points to positions on their halves | |
| int x[2], y[2]; | |
| Fox(j, 2) | |
| { | |
| x[j] = bx[j] ? GetPosAfter(h[0], p[j * 2]) : 2 * INF * (j ? 1 : -1); | |
| y[j] = by[j] ? -GetPosAfter(h[1], p[j * 2 + 1]) : 2 * INF * (j ? 1 : -1); | |
| } | |
| assert(x[0] < x[1] && y[0] < y[1]); | |
| E.pb({ x[0], y[0], y[1], C[i], 1 }); | |
| E.pb({ x[1], y[0], y[1], C[i], 0 }); | |
| CY.pb(y[0]), CY.pb(y[1]); | |
| break; | |
| } | |
| } | |
| // compress Y-coordinates | |
| sort(All(CY)); | |
| int K = unique(All(CY)) - CY.begin(); | |
| CY.resize(K); | |
| // line sweep | |
| SegTree ST(K); | |
| sort(All(E)); | |
| Foxen(e, E) | |
| { | |
| e.y1 = lower_bound(All(CY), e.y1) - CY.begin(); | |
| e.y2 = lower_bound(All(CY), e.y2) - CY.begin(); | |
| // left edge of a rectangle? | |
| if (e.s) | |
| { | |
| ST.Update(e.y1, K - 1, e.c); | |
| continue; | |
| } | |
| // right edge of a rectangle | |
| ST.Update(e.y2, e.y2, ST.Query(e.y2, K - 1) - ST.Query(e.y2, e.y2)); | |
| ST.Update(e.y2 + 1, K - 1, -e.c); | |
| } | |
| return(base + ST.Query(0, K - 1)); | |
| } | |
| int ProcessCase() | |
| { | |
| int i, j; | |
| // input | |
| Read(S), Read(N); | |
| Fox(i, N) | |
| { | |
| Read(C[i]); | |
| Fox(j, 4) | |
| { | |
| int x, y; | |
| Read(x), Read(y); | |
| if (!x) | |
| P[i][j] = y; | |
| else if (y == S) | |
| P[i][j] = S + x; | |
| else if (x == S) | |
| P[i][j] = 3 * S - y; | |
| else | |
| P[i][j] = 4 * S - x; | |
| } | |
| // normalize lines | |
| if (IsBetween(P[i][1], P[i][0], P[i][2], 1)) | |
| swap(P[i][0], P[i][1]); | |
| if (IsBetween(P[i][2], P[i][3], P[i][0], 1)) | |
| swap(P[i][2], P[i][3]); | |
| } | |
| // consider all possible dividing lines | |
| int ans = 0; | |
| Fox(i, N) | |
| { | |
| Fox(j, 2) | |
| Max(ans, SolveForLine({ P[i][j * 2], P[i][j * 2 + 1] })); | |
| } | |
| return(ans); | |
| } | |
| int main() | |
| { | |
| int T, t; | |
| Read(T); | |
| Fox1(t, T) | |
| printf("Case #%d: %d\n", t, ProcessCase()); | |
| return(0); | |
| } |